A 1.30-L sample of argon gas is at 1.02 atm and 21.5°C.?

If the temperature is raised to 500.0°C while the volume remains constant, calculate the new pressure, in atmospheres.


1.86 atm


2.68 atm


1.33 atm


0.67 atm


28.3 atm

A 1.30-L sample of argon gas is at 1.02 atm and 21.5°C.?
Reminder: °C should be converted to Kelvins by adding 273 to the temperature in °C





Use Pressure Law:


P1/T1 = P2/T2


(1.02) / (21.5+273) = P / (500+273)


1.02 / 294.5 = P / 773


P = 2.68atm